对于某个手稿，我需要将图表的标签精确地放在右上角或左上角。标签需要一个与图形的脊椎具有相同厚度的边框。目前我是这样做的：import matplotlib.pyplot as plt

import numpy as np

my_dpi=96

xposr_box=0.975

ypos_box=0.94

nrows=3

Mytext="label"

GLOBAL_LINEWIDTH=2

fig, axes = plt.subplots(nrows=nrows, sharex=True, sharey=True, figsize=

(380/my_dpi, 400/my_dpi), dpi=my_dpi)

fig.subplots_adjust(hspace=0.0001)

colors = ('k', 'r', 'b')

for ax, color in zip(axes, colors):

data = np.random.random(1) * np.random.random(10)

ax.plot(data, marker='o', linestyle='none', color=color)

for ax in ['top','bottom','left','right']:

for idata in range(0,nrows):

axes[idata].spines[ax].set_linewidth(GLOBAL_LINEWIDTH)

axes[0].text(xposr_box, ypos_box , Mytext, color='black',fontsize=8,

horizontalalignment='right',verticalalignment='top', transform=axes[0].transAxes,

bbox=dict(facecolor='white', edgecolor='black',linewidth=GLOBAL_LINEWIDTH))

plt.savefig("Label_test.png",format='png', dpi=600,transparent=True)

因此，我用以下参数控制长方体的位置：

^{pr2}$

如果更改绘图的宽度，则长方体的位置也会更改，但其顶部和右侧(或左侧)脊椎应始终位于图形脊椎的正上方：import matplotlib.pyplot as plt

import numpy as np

my_dpi=96

xposr_box=0.975

ypos_box=0.94

nrows=3

Mytext="label"

GLOBAL_LINEWIDTH=2

fig, axes = plt.subplots(nrows=nrows, sharex=True, sharey=True, figsize=

(500/my_dpi, 400/my_dpi), dpi=my_dpi)

fig.subplots_adjust(hspace=0.0001)

colors = ('k', 'r', 'b')

for ax, color in zip(axes, colors):

data = np.random.random(1) * np.random.random(10)

ax.plot(data, marker='o', linestyle='none', color=color)

for ax in ['top','bottom','left','right']:

for idata in range(0,nrows):

axes[idata].spines[ax].set_linewidth(GLOBAL_LINEWIDTH)

axes[0].text(xposr_box, ypos_box , Mytext, color='black',fontsize=8,

horizontalalignment='right',verticalalignment='top',transform=axes[0].transAxes,

bbox=dict(facecolor='white', edgecolor='black',linewidth=GLOBAL_LINEWIDTH))

plt.savefig("Label_test.png",format='png', dpi=600,transparent=True)

如果图像是窄的而不是像这个例子中的更宽，也应该是这种情况。我希望避免手动操作。有没有办法总是把它放在应该放的地方？独立于地块的宽度和高度

堆积图的数量呢？在