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va.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem&problem=1328

Problem A: Billiard

In a billiard table with horizontal side a inches and vertical side b inches, a ball is launched from the middle of the table. After s > 0 seconds the ball returns to the point from which it was launched, after having made m bounces off the vertical sides and n bounces off the horizontal sides of the table. Find the launching angle A (measured from the horizontal), which will be between 0 and 90 degrees inclusive, and the initial velocity of the ball.

Assume that the collisions with a side are elastic (no energy loss), and thus the velocity component of the ball parallel to each side remains unchanged. Also, assume the ball has a radius of zero. Remember that, unlike pool tables, billiard tables have no pockets.

Input

Input consists of a sequence of lines, each containing five nonnegative integers separated by whitespace. The five numbers are: a, b, s, m, and n, respectively. All numbers are positive integers not greater than 10000.

Input is terminated by a line containing five zeroes.

Output

For each input line except the last, output a line containing two real numbers (accurate to two decimal places) separated by a single space. The first number is the measure of the angle A in degrees and the second is the velocity of the ball measured in inches per second, according to the description above.

Sample Input

100 100 1 1 1200 100 5 3 4201 132 48 1900 1560 0 0 0 0

Sample Output

45.00 141.4233.69 144.223.09 7967.81

1 /************************************************************************* 2
 > File Name: 12345.cpp 3
 > Author: acmicpcstar 4
 > Mail: acmicpcstar@gmail.com 5
 > Created Time: 2014年04月24日 星期四 11时46分18秒 6  ************************************************************************/ 7  8 #include
    
      9 #include
     
      10 #include
      
       11 #include
       
        12 using namespace std;13 const double pi=atan(1.0)*4.0;14 int main()15 {int a,b,s,m,n;16 double h,v,A,p;17 while(cin>>a>>b>>s>>m>>n&&(a!=0||b!=0||s!=0||m!=0))18 {v=b*n;19   h=a*m;20   if(v==0) A=90;21   else A=atan(1.0*v/h)*180/pi;22 p=sqrt(h*h+v*v)/s;23 printf("%0.2lf %0.2lf\n",A,p);24 }25 return 0;26 }
       
      
     
    

我把他桌子平铺相当于不折返而是笔直前进。。。果断Ac。。。90度要特判1下～

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