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用当天的日子对应的星期来推断所给日子的星期

#include 
   
    #include 
    
     #include 
     
      using namespace std;bool isLeapYear(int year) {
   	if (year % 400 == 0 || year % 4 == 0 && year % 100 != 0) return true;	else return false;}int main(){
   	set
      
        bigMonth = {
    1,3,5,7,8,10,12 };	string s1;	int year, month, day;	int year2, month2, day2;	vector
       
         yue = {
    "January", "February","March", "April","May", "June", "July","August","September", "October", "November","December" };	vector
        
          ti = { "Sunday","Monday","Tuesday","Wednesday", "Thursday", "Friday","Saturday" }; while (cin >> day >> s1 >> year) { int num = 0; int i; for (i = 0; i < yue.size(); i++) { if (s1 == yue[i]) break; } month = i + 1; bool big; year2 = 2021; month2 = 2; day2 = 7; int temp; if (year > 2021) { temp = year; year = year2; year2 = temp; temp = month; month = month2; month2 = temp; temp = day; day = day2; day2 = temp; big = true; } else { if (year == 2021 && month > month2) { temp = month; month = month2; month2 = temp; temp = day; day = day2; day2 = temp; big = true; } else if (year == 2021 && month == month2 && day > day2) { temp = day; day = day2; day2 = temp; big = true; } big = false; } while (!(year == year2 && month == month2 && day == day2)) { day++; num++; if (bigMonth.find(month) != bigMonth.end()) { if (day > 31) { month++; day = 1; } } else if (month == 2) { if (isLeapYear(year)) { if (day > 29) { month++; day = 1; } } else { if (day > 28) { month++; day = 1; } } } else { if (day > 30) { month++; day = 1; } } if (month > 12) { year++; month = 1; } } if (big) cout << ti[num % 7] << endl; else cout << ti[6 - ((num-1) % 7)] << endl; }}
        
       
      
     
    
   

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