满意答案

vhfhfh6

2013.04.08

采纳率：50%    等级：12

已帮助：6052人

import javax.swing.JOptionPane;

public class function1

{

public static void main(String[ ] args)

{

double y = 0 ;

int n , i = 1 ;

String n_String;

n_String = JOptionPane. showInputDialog("输入1+1/2+1/3+…+1/n 之n值");

n = Integer.parseInt( n_String );

while( i <= n ){

y = y + 1.0 / i ;

i = i + 1;

}

JOptionPane.showMessageDialog (null,"f("+n+")=1+1/2+…+1/"+n+"="+y,"求函数", JOptionPane.INFORMATION_ MESSAGE);

}

}

编译通过的while循环

for循环

import javax.swing.JOptionPane;

public class function1_for

{

public static void main(String[ ] args)

{

double y = 0 ;

int n , i ;

String n_String;

n_String = JOptionPane. showInputDialog("输入1+1/2+1/3+…+1/n 之n值");

n = Integer.parseInt( n_String );

for( i = 1 ; i <= n ; i++ )

y = y + 1.0 / i ;

JOptionPane.showMessageDialog.

}

}

do循环

import javax.swing.JOptionPane;

public class function1_do

{

public static void main(String[ ] args)

{

double y = 0 ;

int n , i = 0 ;

String n_String;

n_String = JOptionPane. showInputDialog("输入1+1/2+1/3+…+1/n 之n值");

n = Integer.parseInt( n_String );

do{

i++ ;

y = y + 1.0 / i ;

}while( i

JOptionPane.showMessageDialog ( null,"f(" + n + ") = 1+1/2+…+1/" + n +"=" + y,"求函数", JOptionPane. INFORMATION_MESSAGE);

}

}

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