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Calculate a+b and output the sum in standard format – that is, the digits must be separated into groups of three by commas (unless there are less than four digits).

Input Specification:

Each input file contains one test case. Each case contains a pair of integers a and b where −10​6​​≤a,b≤10​6​​. The numbers are separated by a space.

Output Specification:

For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.

Sample Input:

-1000000 9

Sample Output:

-999,991

题目概述：

分析：

//从后到前加,#include
   
    using namespace std;int main(){
       int a, b;    scanf("%d%d", &a, &b);    int sum = a + b;    if(sum < 0) printf("-");    string str1 = to_string(abs(sum));    string str2;    for(int i = 0; i < str1.size(); i++)    {
           str2 += str1[str1.size() - 1 - i];        if((i + 1) % 3 == 0 && i != str1.size() - 1) str2 += ',';    }    reverse(str2.begin(),str2.end());    printf("%s", str2.c_str());    printf("\n");    return 0;}
   

总结：

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