本文共 2783 字，大约阅读时间需要 9 分钟。

制作样本级的时候需要用，统一把采集的乱七八糟的文件夹遍历，并统一输出统一命名；

Mac xcode

#include 
   
    #include 
    
     #include 
     
      #include 
      
       #include 
       
        #include 
        
         #include 
         
          #include 
          
           #include 
           
            #include 
            
             #include 
             
              #include 
              
               #include 
               
                #include 
                
                 #include 
                 
                  using namespace cv;using namespace std;inline void get_dirs_files(string dir ,vector
                  
                    &vec_dir, vector
                   
                     &vec_file){ if( dir.empty() ) { cout<<" dir is null ! "<
                    
                     d_name , "." ) == 0 || strcmp( filename->d_name , "..") == 0 ) continue; if(filename->d_type == 4)//dir { //cout<< "dir: " << filename->d_name <
                     
                      d_name)); } else if(filename->d_type == 8)//file { //cout<< "file: " << filename->d_name <
                      
                       d_name)); } }}int main(int argc, const char * argv[]) { vector
                       
                         vec_dir; vector
                        
                          vec_file; static vector
                         
                           vec_image; string dir_root = "/Users/TNC/Desktop/codebase/traincascade/traincascade/data/ng"; get_dirs_files(dir_root,vec_dir,vec_file); // printf("含有文件夹数目：%d\n",vec_dir.size()); //遍历所有文件夹的文件名 /* 目前只是遍历一级目录，若有其他需求自行修改 */ for(int i=0;i
                          
                            vec_dir2; vector
                           
                             vec_file2; get_dirs_files(dir_root+"/"+vec_dir[i],vec_dir2,vec_file2); for(int j=0;j
                            
                             ::iterator iter = vec_image.begin(); string path = "/Users/TNC/Desktop/codebase/traincascade/traincascade/data/bg/"; int index=0; while(iter != vec_image.end()) { char fn[256]; char dir[256]; index ++; Mat image = imread((*iter).c_str()); sprintf(fn,"%s%d.jpg",path.c_str(),index); imwrite(fn, image); cout << "已输出：" << index << endl; iter ++; } } else { cout << "文件夹为空" << endl; } return 0;}
                            
                           
                          
                         
                        
                       
                      
                     
                    
                   
                  
                 
                
               
              
             
            
           
          
         
        
       
      
     
    
   

Win Visual Studio

32位：

64位：采用上面常规方法会报错，需要调整：

#include 
   
    #include 
    
     #include 
     
      #include 
      
       using namespace std;using namespace cv;vector
       
         vec_path;int main(){		__int64  Handle;	long jpg_num = 0;	struct __finddata64_t FileInfo;	char rootpath[256] = "F:\\workplace\\cascade\\train_images\\";	int count = 0;		char tmp_path[256];	sprintf_s(tmp_path, "%s*.jpeg", rootpath);//临时文件路径	if ((Handle = _findfirst64(tmp_path, &FileInfo)) == -1L)			printf("没有找到匹配的项目\n");	else	{		//遍历文件夹下的所有文件		printf("%s\n", FileInfo.name);		while (_findnext64(Handle, &FileInfo) == 0) 		{			//生成绝对路径					char filepath[256];					sprintf_s(filepath, "%s%s", rootpath, FileInfo.name);					printf("%s\n", filepath);					vec_path.push_back(filepath);					count++;		}		_findclose(Handle);	}	if (!vec_path.empty())	{		vector
        
         ::iterator iter = vec_path.begin(); int index = 1; //输出目标路径 char out_path[256] = "F:\\workplace\\cascade\\samples\\"; while (iter != vec_path.end()) { Mat img = imread((*iter)); if (!img.empty()) { char img_path[256]; sprintf_s(img_path, "%s%d.jpeg", out_path, index); imwrite(img_path, img); printf("输出序号：%d / %d\n", index, count); } index++; iter++; } } return 0;}
        
       
      
     
    
   

转载地址：https://chenlinwei.blog.csdn.net/article/details/92832942 如侵犯您的版权，请留言回复原文章的地址，我们会给您删除此文章，给您带来不便请您谅解！