本文共 3359 字，大约阅读时间需要 11 分钟。

00. 目录

01. if 结构一

.section .rodata    .align 2.LC0:    .string "i > 10\n".LC1:    .string "i <= 10\n"    .section .text    .align 2    .global mainmain:    push {lr}    mov r2, #1    cmp r2, #10    ldrgt r0, =.LC0    ldrle r0, =.LC1        bl printf    mov r0, #0    pop {pc}

02. if 结构二

.section .rodata    .align 2.LC0:    .string "i > 10\n".LC1:    .string "i <= 10\n"    .section .text    .align 2    .global mainmain:    push {lr}    mov r2, #1    cmp r2, #10    bgt do1    b do2do1:    ldr r0, =.LC0    bl printf    b outdo2:    ldr r0, =.LC1    bl printfout:    mov r0, #0    pop {pc}

03. if 结构三

.section .rodata    .align 2.LC0:    .string "i > 10\n".LC1:    .string "i < 10\n".LC2:    .string "i == 10\n"    .section .text    .align 2    .global mainmain:    push {lr}    mov r2, #1    cmp r2, #10    bgt do1    blt do2    b do3do1:    ldr r0, =.LC0    bl printf    b outdo2:    ldr r0, =.LC1    bl printf    b outdo3:    ldr r0, =.LC2    bl printfout:    mov r0, #0    pop {pc}

04. if 结构四

if(i > 10)		...	else if(i + j > 10)		...	else if(j < 10)		...

.section .rodata    .align 2.LC0:    .string "i > 10\n".LC1:    .string "i + j > 10\n".LC2:    .string "j < 10\n"    .section .text    .align 2    .global mainmain:    push {lr}    mov r2, #100    mov r3, #2    cmp r2, #10    bgt do1        add r1, r2, r3    cmp r1, #10    bgt  do2    cmp r3, #10    blt do3    b outdo1:    ldr r0, =.LC0    bl printf    b outdo2:    ldr r0, =.LC1    bl printf    b outdo3:    ldr r0, =.LC2    bl printfout:    mov r0, #0    pop {pc}

05. if 结构五

.section .rodata    .align 2.LC0:    .string "i > 10 && i < 20\n"    .section .text    .align 2    .global mainmain:    push {lr}    mov r2, #15    cmp r2, #10    ble out    cmp r2, #20    blt do1    b outdo1:    ldr r0, =.LC0    bl printfout:    mov r0, #0    pop {pc}

06. switch结构

C语言代码

#include 
   
    int main(void){
   	int i = 10;	char ch = 'a';	switch(i)	{
   		case 1:			printf("val = %d \n", i);			break;		case 345:			printf("val = %d \n", i);			break;		case 23:				printf("val = %d \n", i);			break;		case 7:			printf("val = %d \n", i);			break;		case 1234:			printf("val = %d \n", i);			break;		case 17:			printf("val = %d \n", i);			break;		case 10:			printf("val = %d \n", i);			break;	}		return 0;}
   

汇编语言代码

.section	.rodata	.align	2.LC0:	.ascii	"val = %d \012\000"	.text	.align	2	.global	mainmain:	stmfd	sp!, {fp, lr}	add	fp, sp, #4	sub	sp, sp, #8	mov	r3, #10	str	r3, [fp, #-8]	mov	r3, #97	strb	r3, [fp, #-9]	ldr	r3, [fp, #-8]	cmp	r3, #17	beq	.L6	cmp	r3, #17	bgt	.L10	cmp	r3, #7	beq	.L4	cmp	r3, #10	beq	.L5	cmp	r3, #1	beq	.L3	b	.L2.L10:	ldr	r2, .L11	cmp	r3, r2	beq	.L8	ldr	r2, .L11+4	cmp	r3, r2	beq	.L9	cmp	r3, #23	beq	.L7	b	.L2.L3:	ldr	r3, .L11+8	mov	r0, r3	ldr	r1, [fp, #-8]	bl	printf	b	.L2.L8:	ldr	r3, .L11+8	mov	r0, r3	ldr	r1, [fp, #-8]	bl	printf	b	.L2.L7:	ldr	r3, .L11+8	mov	r0, r3	ldr	r1, [fp, #-8]	bl	printf	b	.L2.L4:	ldr	r3, .L11+8	mov	r0, r3	ldr	r1, [fp, #-8]	bl	printf	b	.L2.L9:	ldr	r3, .L11+8	mov	r0, r3	ldr	r1, [fp, #-8]	bl	printf	b	.L2.L6:	ldr	r3, .L11+8	mov	r0, r3	ldr	r1, [fp, #-8]	bl	printf	b	.L2.L5:	ldr	r3, .L11+8	mov	r0, r3	ldr	r1, [fp, #-8]	bl	printf	mov	r0, r0	@ nop.L2:	mov	r3, #0	mov	r0, r3	sub	sp, fp, #4	ldmfd	sp!, {fp, pc}.L12:	.align	2.L11:	.word	345	.word	1234	.word	.LC0	.size	main, .-main	.ident	"GCC: (ctng-1.8.1-FA) 4.5.1"	.section	.note.GNU-stack,"",%progbits

07. 附录

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