Babelfish

Time Limit: 3000MS		Memory Limit: 65536K
Total Submissions: 49919		Accepted: 20820

Description

You have just moved from Waterloo to a big city. The people here speak an incomprehensible dialect of a foreign language. Fortunately, you have a dictionary to help you understand them.

Input

Input consists of up to 100,000 dictionary entries, followed by a blank line, followed by a message of up to 100,000 words. Each dictionary entry is a line containing an English word, followed by a space and a foreign language word. No foreign word appears more than once in the dictionary. The message is a sequence of words in the foreign language, one word on each line. Each word in the input is a sequence of at most 10 lowercase letters.

Output

Output is the message translated to English, one word per line. Foreign words not in the dictionary should be translated as "eh".

Sample Input

dog ogdaycat atcaypig igpayfroot ootfrayloops oopslayatcayittenkayoopslay

Sample Output

catehloops

Hint

Huge input and output,scanf and printf are recommended.

Source

大致题意：

输入一个字典，字典格式为“英语 -> 外语”的一一映射关系

然后输入若干个外语单词，输出他们的英语翻译单词，如果字典中不存在这个单词，则输出“eh”

解题思路：

第一次使用map,并且使用到了char数组到string转化的函数assign。

这道题的难点在于，判断输入。下面有两种方法。

代码：

#include 
   
    #include 
    
     #include 
     
       #include 
      using namespace std;int main(){     map
       
         dic;    map
        
          flag; string word,foreign; char s1[20],s2[20]; char *p=s1,*q=s2; while(true) { scanf("%s",p); //输入第一个字符串 char temp=getchar(); if(temp=='\n') //若输入换行符直接跳出循环 break; scanf("%s",q); //输入第二个匹配的字符串 getchar(); word.assign(p,strlen(p)); //将字符串转化为string foreign.assign(q,strlen(q)); dic[foreign]=word; //第二个cmp flag[foreign]=true; //第一个cmp } foreign.assign(p,strlen(p));//第一个输入的放在p中 if(!flag[foreign]) cout << "eh" << endl; else cout << dic[foreign] << endl; while(cin >> foreign) { if(!flag[foreign]) cout << "eh" << endl; else cout << dic[foreign] << endl; } return 0;}

#include
   
    #include
    
     #include
     using namespace std; int main(void){    char english[11],foreign[11];     map
      
       appear;  //记录foreign与engliash的配对映射是否出现    map
       
        translate; //记录foreign到engliash的映射     /*Input the dictionary*/     while(true)    {        char t;  //temporary         if((t=getchar())=='\n')  //判定是否输入了空行            break;        else     //输入english        {            english[0]=t;            int i=1;            while(true)            {                t=getchar();                if(t==' ')                {                    english[i]='\0';                    break;                }                else                    english[i++]=t;            }        }         cin>>foreign;        getchar();  //吃掉 输入foreign后的 回车符         appear[foreign]=true;        translate[foreign]=english;    }     /*Translate*/     char word[11];    while(cin>>word)    {        if(appear[word])            cout<
        
         <

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