本文共 309 字，大约阅读时间需要 1 分钟。

题目链接：

题目大意：略。

解题思路：略。

AC 代码

-- 解决方案(1)WITH t1 AS(SELECT *FROM my_numbersGROUP BY numHAVING COUNT(*) = 1ORDER BY num DESCLIMIT 1)SELECT IF(COUNT(*) = 0, null, num) AS `num`FROM t1-- 解决方案(2)SELECT    MAX(num) AS numFROM    (SELECT        num    FROM        number    GROUP BY num    HAVING COUNT(num) = 1) AS t;

转载地址：https://lux-sun.blog.csdn.net/article/details/117932648 如侵犯您的版权，请留言回复原文章的地址，我们会给您删除此文章，给您带来不便请您谅解！