PAT 甲级 1008 Elevator
发布日期:2021-07-01 03:08:45 浏览次数:3 分类:技术文章

本文共 1692 字,大约阅读时间需要 5 分钟。

1008 Elevator (20 point(s))

The highest building in our city has only one elevator. A request list is made up with N positive numbers. The numbers denote at which floors the elevator will stop, in specified order. It costs 6 seconds to move the elevator up one floor, and 4 seconds to move down one floor. The elevator will stay for 5 seconds at each stop.

For a given request list, you are to compute the total time spent to fulfill the requests on the list. The elevator is on the 0th floor at the beginning and does not have to return to the ground floor when the requests are fulfilled.

Input Specification:

Each input file contains one test case. Each case contains a positive integer N, followed by N positive numbers. All the numbers in the input are less than 100.

Output Specification:

For each test case, print the total time on a single line.

Sample Input:

3 2 3 1

Sample Output:

41

Experiential Summing-up

This problem is so easy, so I don't said more about it.~

 (The purpose of using English to portray my solution is that to exercise the ability of my expression of English and accommodate PAT advanced level's style.We can make progress together by reading and comprehending it. Please forgive my basic grammar's and word's error. Of course, I would appreciated it if you can point out my grammar's and word's error in comment section.( •̀∀•́ ) Furthermore, Big Lao please don't laugh at me because I just a English beginner settle for CET6    _(:з」∠)_  )

Accepted Code 

#include 
int main(){ int n,t; scanf("%d",&n); int total=0,pos=0; for(int i=0;i
pos) { total+=(t-pos)*6; } else { total+=(pos-t)*4; } pos=t; total+=5; } printf("%d\n",total); return 0;}

 

转载地址:https://meteorrain.blog.csdn.net/article/details/86522090 如侵犯您的版权,请留言回复原文章的地址,我们会给您删除此文章,给您带来不便请您谅解!

上一篇:PAT 甲级 1009 Product of Polynomials
下一篇:PAT 甲级 1007 Maximum Subsequence Sum

发表评论

最新留言

留言是一种美德,欢迎回访!
[***.207.175.100]2024年04月15日 11时46分25秒