本文共 1353 字，大约阅读时间需要 4 分钟。
数组拆分处理(整数时的处理)
已知数组a：
array (
0 =>
array (
'po_num' => '20131227-000008102',
'plant' => 'JQSP',
'get_date' => '2013-12-27',
'cust_no' => '12654172',
'total' => '225',
'snp' => '15',
'mount' => '15',
'lp_no' => 'P000000D',
),
)
处理程序如下：
$t = 225;
$k = 0;
foreach($a as $v) {
$t1 = $v['total'];
$v['total'] = $t1 % $t;
$res[$k][] = $v;
$t1 -= $v['total'];
while($t1 >= $t) {
$v['total'] = $t;
$t1 -= $t;
$res[++$k][] = $v;
}
}
$res = array_reverse($res);
print_r($res);
得到的结果：
Array
(
[0] => Array
(
[0] => Array
(
[po_num] => 20131227-000008102
[plant] => JQSP
[get_date] => 2013-12-27
[cust_no] => 12654172
[total] => 225
[snp] => 15
[mount] => 15
[lp_no] => P000000D
)
)
[1] => Array
(
[0] => Array
(
[po_num] => 20131227-000008102
[plant] => JQSP
[get_date] => 2013-12-27
[cust_no] => 12654172
[total] => 0 //产生了为0的项
[snp] => 15
[mount] => 15
[lp_no] => P000000D
)
)
)
既然是整除，那么结果应该只有一项，如何修改代码让其只有非0项生成？
------解决方案--------------------
本帖最后由 xuzuning 于 2013-12-27 15:34:48 编辑
$a = array (
0 =>
array (
'po_num' => '20131227-000008102',
'plant' => 'JQSP',
'get_date' => '2013-12-27',
'cust_no' => '12654172',
'total' => '225',
'snp' => '15',
'mount' => '15',
'lp_no' => 'P000000D',
),
);
$t = 225;
$k = 0;
foreach($a as $v) {
$t1 = $v['total'];
if($t1 % $t) $v['total'] = $t1 % $t;
$res[$k][] = $v;
$t1 -= $v['total'];
while($t1 >= $t) {
$v['total'] = $t;
转载地址：https://blog.csdn.net/weixin_32467749/article/details/116415802 如侵犯您的版权，请留言回复原文章的地址，我们会给您删除此文章，给您带来不便请您谅解！
发表评论
最新留言
关于作者
